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Consider the sequence given by the recursion a0 = 1, a1=1/3, an+1 = 2/3*an - an-1 (n ≥ 1). Prove that there exists a positive integer n such that an > 0.9999. I wrote a program, and I found that a245 = 0.999969287. Can anybody give an exact mathematical proof? |
| Investigation:
Wow, that sequence is a real cement mixer! It seems to rise and fall like the tide, with a period of about 6411/1256. I notice a832 = 0.999999529702558, and a6411 = 0.999999996898893. The "high tides" also follow a cycle with a non-integral period of about 6411/131. I would make a conjecture that for any ε, an n can be found such that 1-an < ε. I would like to see a proof of that. Here is a graph of an vs. n:
In the above graph, you can see that there is a local maximum with a period of about 5, but not exactly 5. Furthermore, there is a second-order period that is apparent in which the local maxima get closer to one about every 50 iterations, but, again, not exactly 50. Here is a graph of the apparent period of this function vs. n:
And here is a graph of the apparent second-order period that you can see in the first graph.
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